Formation of hydroxyl radicals by irradiated 1-nitronaphthalene (1NN): oxidation of hydroxyl ions and water by the 1NN triplet state
Photochemical & Photobiological Sciences, 2011•pubs.rsc.org
The excited triplet state of 1-nitronaphthalene (31NN*) reacts with OH− with a second-order
reaction rate constant of (1.66±0.08)× 107 M− 1s− 1 (μ±σ). The reaction yields the˙ OH
radical and the radical anion 1NN−˙. In aerated solution, the radical 1NN−˙ would react with
O2 to finally produce H2O2 upon hydroperoxide/superoxide disproportionation. The
photolysis of H2O2 is another potential source of˙ OH, but such a pathway would be a minor
one in circumneutral (pH 6.5) or in basic solution ([OH−]= 0.3–0.5 M). The oxidation of H2O …
reaction rate constant of (1.66±0.08)× 107 M− 1s− 1 (μ±σ). The reaction yields the˙ OH
radical and the radical anion 1NN−˙. In aerated solution, the radical 1NN−˙ would react with
O2 to finally produce H2O2 upon hydroperoxide/superoxide disproportionation. The
photolysis of H2O2 is another potential source of˙ OH, but such a pathway would be a minor
one in circumneutral (pH 6.5) or in basic solution ([OH−]= 0.3–0.5 M). The oxidation of H2O …
The excited triplet state of 1-nitronaphthalene (31NN*) reacts with OH− with a second-order reaction rate constant of (1.66 ± 0.08)×107 M−1s−1 (μ ± σ). The reaction yields the ˙OH radical and the radical anion 1NN−˙. In aerated solution, the radical 1NN−˙ would react with O2 to finally produce H2O2 upon hydroperoxide/superoxide disproportionation. The photolysis of H2O2 is another potential source of ˙OH, but such a pathway would be a minor one in circumneutral (pH 6.5) or in basic solution ([OH−] = 0.3–0.5 M). The oxidation of H2O by 31NN*, with rate constant 3.8 ± 0.3 M−1s−1, could be the main ˙OH source at pH 6.5.
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