Direct summands of direct sums of modules whose endomorphism rings have two maximal right ideals
A Amini, B Amini, A Facchini - Journal of Pure and Applied Algebra, 2011 - Elsevier
Let M1,…, Mn be right modules over a ring R. Suppose that the endomorphism ring EndR
(Mi) of each module Mi has at most two maximal right ideals. Is it true that every direct …
(Mi) of each module Mi has at most two maximal right ideals. Is it true that every direct …
On essential extensions of direct sums of either injective or projective modules
For a ring R, there are classical facts that R is right Noetherian if and only if every direct sum
of injective right R-modules is injective, and R is right Noetherian if and only if every …
of injective right R-modules is injective, and R is right Noetherian if and only if every …
When direct sums of singular injectives are injective
SS Page, Y Zhou - Ring theory (SK Jain and S. Tariq Rizvi, eds.) …, 1993 - books.google.com
Let R be an associative ring with identity. We show that every direct sum of singular injective
right R-modules is injective iff any one of the following equivalent conditions holds. i) Every …
right R-modules is injective iff any one of the following equivalent conditions holds. i) Every …
On rings with associated elements
MT Koşan, TC Quynh, S Şahinkaya - Communications in Algebra, 2017 - Taylor & Francis
ABSTRACT A principal right ideal of a ring is called uniquely generated if any two elements
of the ring that generate the same principal right ideal must be right associated (ie, if for all a …
of the ring that generate the same principal right ideal must be right associated (ie, if for all a …
[PDF][PDF] Finitely Presented Right Modules Over a Left Pure‐Semisimple Ring
I Herzog - Bulletin of the London Mathematical Society, 1994 - academia.edu
In this note, we study rings over which every left module is a direct sum of finitely generated
modules. Chase [5] showed that all such rings are left artinian and Fuller [8] proved that …
modules. Chase [5] showed that all such rings are left artinian and Fuller [8] proved that …
Endomorphism rings with finitely many maximal right ideals
A Facchini, P Příhoda - Communications in Algebra, 2011 - Taylor & Francis
We show that the indecomposable R-modules whose endomorphism ring has finitely many
maximal right ideals, all of them two-sided, have a surprisingly simple behavior as far as …
maximal right ideals, all of them two-sided, have a surprisingly simple behavior as far as …
[PDF][PDF] Essential extensions of a direct sum of simple modules
KI Beidar, SK Jain, AK Srivastava - Contemporary Mathematics, 2006 - researchgate.net
It is known that every essential extension of a direct sum of injective hulls of simple R-
modules is a direct sum of injective R-modules if and only if the ring R is right noetherian …
modules is a direct sum of injective R-modules if and only if the ring R is right noetherian …
Rings whose pure-injective right modules are direct sums of lifting modules
PAG Asensio, DK Tütüncü - Journal of Algebra, 2013 - Elsevier
It is shown that every pure-injective right module over a ring R is a direct sum of lifting
modules if and only if R is a ring of finite representation type and right local type. In …
modules if and only if R is a ring of finite representation type and right local type. In …
The rational hull of modules
G Lee - arXiv preprint arXiv:2309.12621, 2023 - arxiv.org
In this paper, we provide several new characterizations of the maximal right ring of quotients
of a ring by using the relatively dense property. As a ring is embedded in its maximal right …
of a ring by using the relatively dense property. As a ring is embedded in its maximal right …
Modules with coindependent maximal submodules
PF Smith - Journal of Algebra and Its Applications, 2011 - World Scientific
Let R be a ring with identity. A unital left R-module M has the min-property provided the
simple submodules of M are independent. On the other hand a left R-module M has the …
simple submodules of M are independent. On the other hand a left R-module M has the …