Approach your problems from the right end It isn't! hat they can't see the solution. It is and
begin with the answers. Then one day, that they can't see the problem. perhaps you will find …

This paper reviews the early axiomatic treatments of quasi-linear means developed in the
late 1920s and the 1930s. These years mark the beginning of both axiomatic and …

ON SOME FUNCTIONAL INEQUALITIES RELATED TO THE LOGARITHMIC MEAN Page 1
Acta Math. Hungar., 128 (1–2) (2010), 36–45. DOI: 10.1007/s10474-010-9153-3 First …

The aim of this paper is to characterize in broad classes of means the so-called Hardy
means, ie, those means $ M\colon\bigcup_ {n= 1}^\infty\mathbb {R} _+^ n\to\mathbb {R} _+ …

The aim of this paper is to characterize the so-called Hardy means, ie, those means $
M\colon\bigcup_ {n= 1}^\infty\mathbb {R} _+^ n\to\mathbb {R} _+ $ that satisfy the inequality …

On applications of inequalities for quasideviation means in actuarial mathematics Page 1 M
athematical I nequalities & A pplications Volume 21, Number 3 (2018), 601–610 doi:10.7153/mia-2018-21-44 …

We solve the comparison problem for generalized\(\psi\)-estimators introduced by Barczy
and Páles (arXiv: 2211.06026, 2022). Namely, we derive several necessary and sufficient …

Given two continuous functions f, g: I→ R such that g is positive and f/g is strictly monotone,
and a probability measure μ on the Borel subsets of [0, 1], the two variable mean Mf, g; μ …

Minkowski’s inequality for two variable Gini means Page 1 Minkowski’s inequality for two
variable Gini means László Losonczi ∗ Department of Mathematics and Computer Science …

This paper offers a solution of the functional equation &\big (tf (x)+(1-t) f (y)\big) φ (tx+ (1-t)
y)\&\quad= tf (x) φ (x)+(1-t) f (y) φ (y)\qquad (x, y ∈ I),(tf (x)+(1-t) f (y)) φ (tx+(1-t) y)= tf (x) φ …